# Mary’s farm stand sold a total of 165 pounds of apples and peaches. She sold apples for \$1.75 per pound and peaches for \$2.50 per pound. If she made \$337.50 how many apples and how many peaches did she sell?

Algebra

The weight of apples is: 100 The weight of pairs is: 65

Just \$7 Welcome

Let the mass in pounds of apples be##” ” a## Let the mass in pounds of pairs be ##” “p##

Let total income from apples be ##” “T_a##

Let the total income from pairs be ##” “T_p##

##color(blue)(“Breaking the question into parts to build the equations:”)##

Sold a total of 165 pound of apples##” “->a+p=165## ….(1)

Sold apples for \$1.75 per pound ##” “-> T_a=1.75xxa##….(2) Sold pairs for \$2.50 per pound##” “->T_p=pxx2.50##….(3)

She made \$337.50 ##” “->T_a+T_p=337.50##…..(4) ‘~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

##color(blue)(“Determine the value of p”)##

From equation (1) ##color(brown)(a=165-p” “……….(1_a))##

Substituting equations (2) and (3) into (4)

##T_a+T_p=337.50″ “->” “1.75color(green)(a)+2.5p=337.50##

But from ##(1_a) ” “color(green)(a)=165-p## giving

##T_a+T_p=337.50″ “->” “1.75(color(green)(165-p))+2.5p=337.50##

##288.75-1.75p+2.5p=337.5##

##288.75 +0.75p=337.5##

##p=(337.5-288.75)/(0.75)##

##color(red)(p= 65)##…………………………………(5) ‘~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##color(blue)(“Determine the value of a”)##

Substitute equation (5) into equation (1)

##a+color(green)(p)=165″ “->” “a+color(green)(65)=165##

##a=165-65 = 100##

##color(red)(a=100)## .~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Check: ##\$1.75(100) + \$2.50(65)” “=” “\$175+\$162.5” “=” “\$337.5 ” “-> color(red)(“True”)##